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Published On:Friday, 9 December 2011
Posted by Muhammad Atif Saeed

Graphs of Linear Inequalities

Graphs of Linear Inequalities

A linear inequality is a sentence in one of the following forms:
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  • Ax + By < C

  • Ax + By > C

  • Ax + ByC

  • Ax + ByC

  • To graph such sentences
    1. Graph the linear equation Ax + By = C. This line becomes a boundary line for the graph. If the original inequality is < or >, the boundary line is drawn as a dashed line, since the points on the line do not make the original sentence true. If the original inequality is ≤ or ≥, the boundary line is drawn as a solid line, since the points on the line will make the original inequality true.
    2. Select a point not on the boundary line and substitute its x and y values into the original inequality.
    3. Shade the appropriate area. If the resulting sentence is true, then shade the region where that test point is located, indicating that all the points on that side of the boundary line will make the original sentence true. If the resulting sentence is false, then shade the region on the side of the boundary line opposite that where the test point is located.
    Example 1
    Graph 3 x + 4 y < 12.
    First, draw the graph of 3 x + 4 y = 12. If you use the x-intercept and y-intercept method, you get x-intercept (4,0) and y-intercept (0,3). If you use the slope-intercept method, the equation, when written in slope-intercept ( y = mx + b) form, becomes
    equation
    Because the original inequality is <, the boundary line will be a dashed line. Look at Figure 1.
    Now select a point not on the boundary, say (0,0). Substitute this into the original inequality:
    equation
    This is a true statement. This means that the “(0,0) side” of the boundary line is the desired region to be shaded. Now, shade that region as shown in Figure 2.
    Figure 1. The boundary is dashed.
    figure
    Figure 2. The shading is below the line.
    figure
    Example 2
    Graph y ≥ 2 x + 3.
    First, graph y = 2 x + 3 (see Figure 3).
    Notice that the boundary is a solid line, because the original inequality is ≥. Now, select a point not on the boundary, say (2,1), and substitute its x and y values into y ≥ 2 x + 3.
    equation
    This is not a true statement. Because this replacement does not make the original sentence true, shade the region on the opposite side of the boundary line (see Figure 4).
    Figure 3. This boundary is solid.
    figure
    Figure 4. Shading shows greater than or equal to.
    figure
    Example 3
    Graph x < 2.
    The graph of x = 2 is a vertical line whose points all have the x-coordinate of 2 (see Figure 5).
    Select a point not on the boundary, say (0,0). Substitute the x value into x < 2.
    equation
    This is a true statement. Therefore, shade in the “(0,0) side” of the boundary line (see Figure 6).
    Figure 5. Dashed graph of x = 2.
    figure
    Click here to find out more!
    Figure 6. x less than 2 is shaded.
    figure

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    Posted by Muhammad Atif Saeed on 00:51. Filed under . You can follow any responses to this entry through the RSS 2.0. Feel free to leave a response

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    I am doing ACMA from Institute of Cost and Management Accountants Pakistan (Islamabad). Computer and Accounting are my favorite subjects contact Information: +923347787272 atifsaeedicmap@gmail.com atifsaeed_icmap@hotmail.com

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